When Fixed At Both Ends, And Loaded In The Middle
Description
This section is from the book "The English And American Mechanic", by B. Frank Van Cleve. Also available from Amazon: The English And American Mechanic.
When Fixed At Both Ends, And Loaded In The Middle
Rule
Multiply the weight to be supported in pounds by the length of the cylinder between the supports in feet; divide the product by .6 of the value of the material, and the cube root of ¼ of the quotient will give the diameter.
The strength of a Rectangle, the diagonal being vertical compared to that of its circumscribing rectangle, when the direction of the strain Is parallel to the side of it, is as 2.45 to 1.
Note
When the cylinder is loaded uniformly along its length, the cube root of half the quotient will give the diameter.
Example
What should be the diameter of a cast-iron cylinder, 2 feet between the supports, that will support 1930s lbs. without permanent injury?
19305X2 286
------------ 286, and 3√-- 8.61 ins. .6X225 6
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